| Comments |
p.144 right column 4th paragraph: "Based on Eq. 2 (and assuming ?x'??x), [investigators] considered several biological specimens (gathered in Table 2) and displayed them according to their speed and the required spatial resolution in the graph of Fig. 2." Note above table:"Processes are ordered according to increasing frame rates (f) that are required to image them at a resolution ?x'. [Investigators] calculated f using a simplified version of Eq. 2, f=v/?x' where ?x' was taken to be 1/10th of the imaged structure size. Note how slow processes can require high framerates since f also depends on the required imaging resolution. For example, the motion of broken DNA ends is slow (1 nm/s, the slowest process in the table) but it ranks fourth according to required frame rate." |