# Rate of oxygen utilization to combust daily requirement of food for 70kg male (assuming 10^14 cells in body)

Value 2.5E-18 mol/cell/sec Human Homo sapiens Wagner BA, Venkataraman S, Buettner GR. The rate of oxygen utilization by cells. Free Radic Biol Med. 2011 Aug 1 51(3):700-12. doi: 10.1016/j.freeradbiomed.2011.05.024 abstract & p.700 right column bottom paragraphPubMed ID21664270 Abstract: "Humans use oxygen to extract approximately 2550 calories (10.4 MJ) from food to meet daily energy requirements. This combustion requires about 22 mol of dioxygen per day, or 2.5×10^-4 mol/sec. This is an average rate of oxygen utilization of 2.5×10^-18 mol/cell/sec, i.e., 2.5 amol/cell/sec." P.700 right column bottom paragraph: "Humans use this oxygen to extract approximately 2550 calories (10.4 MJ for a 70-kg, 20-year-old male [BNID 115147, ref 5]) from food to meet daily energy requirements. This combustion requires approximately 22 mol of dioxygen per day, or 2.5 × 10^−4 mol/sec. For a 70-kg person, this rate of O2 uptake is 3.6×10^−9 mol/sec/g. If the typical 70-kg person consists of 1×10^14 cells, then the average rate of oxygen utilization per cell would be 2.5×10^−18 mol/cell/sec, i.e., 2.5 amol/cell/sec." amol=attomol=10^-18 mol Uri M 115149