Maximum ATP yield from full oxidation of one molecule of glucose

Value ~29.85 ATP
Organism Generic
Reference Rich, PR. The molecular machinery of Keilin's respiratory chain. Biochem Soc Trans. 2003 Dec31(Pt 6) 1095-105. p.1103 right column 2nd paragraphPubMed ID14641005
Method 6.6 ATP from glycolysis (glucose>>2 pyruvate: 4.6 from 2 NADH, and 2 directly), 4.6 ATP from 2 pyruvate >> 2 acetyl-CoA, and 18.6 from the TCA cycle (including 2 ATP from 2 GTP). In other words, 112 H+ are translocated by 10 NADH (10 H+ each) and 2 succinate (6 H+ each). Since the H+/ATP ratio is 13:3, this results in 25.85 ATP. 2 more come from glycolysis, and 2 more from GTP conversion.
Comments "Hence the net synthesis of cytoplasmic ATP from ADP should operate at a ratio of 13:3 H+/ATP. As a result, oxidation of NADH is expected to produce 3×10/13 2.3 ATP and oxidation of succinate 3×6/13 1.4 ATP. This would predict that the maximum yield of ATP from full oxidation of one glucose molecule should be: glucose 2 pyruvate, 6.6 ATP: 2 pyruvate 2 acetyl-CoA, 4.6 ATP: citric acid cycle, 18.6 ATP (with two ATP from two GTP). Oxidation of the whole ten NADH and two succinate would result in translocation of 112 H+, giving an overall yield, with two ATP from two GTP, of 29.85 ATP/glucose (or 29.38 ATP/glucose if the GTP-derived ATP also has to be exported)." This includes the production of two ATP from two GTP during the citric acid cycle. If these two ATP need to be exported, the maximum ATP yield decreases to 29.38 ATP/glucose.
Entered by Phil Mongiovi
ID 101778